sandrine62 Posted February 7, 2005 Share Posted February 7, 2005 ce qui donne x+3x+9x=1560 13x=1560 x=1560/13 x=520 le vendredi 520 tickets ont été vendus il reste donc 1040 tickets.comment les répartir entre samedi et dimanche? Link to comment Share on other sites More sharing options...
woodette Posted February 7, 2005 Share Posted February 7, 2005 soit V, S et D le nb de tichets vendus vendredi, saledi et dimanche. V + S + D = 1560 S = 3 V D = 3 S = 3 (3 V) = 9 V Tu remplaces dans la première équation : V + S + D = 1560 V + (3 V) + (9 V) = 1560 13 V = 1560 V = 1560/13 = 120 (et non pas 520 sandrine ) Ensuite ayant V tu déduis S et D : S = 3 V = 3 x 120 = 360 D = 3 S = 9 V = 9 x 120 = 1080 Donc la réponse est : V = 120 S = 360 D = 1080 Voili, voilou Link to comment Share on other sites More sharing options...
Penelope Posted February 7, 2005 Share Posted February 7, 2005 C'est ça, d'ailleurs 1080 + 360 + 120 = 1560 Link to comment Share on other sites More sharing options...
sandrine62 Posted February 7, 2005 Author Share Posted February 7, 2005 ok merci. pas étonnant que je n'arrivais pas à résoudre l'équation puisque j'avais fait une erreur de calcul au départ. Link to comment Share on other sites More sharing options...
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